Math, asked by kajalmishra7874, 4 months ago

find nth derivative of a^x.cosx

Answers

Answered by hs311295
0

please refer attachment

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kajalmishra7874: plz upload its solution also
kajalmishra7874: its first deivative.
hs311295: can't...there no option for that once u give ans...if u hv any option tell me
kajalmishra7874: we have to find nth derivative
hs311295: u mean [a^x•cosx]^n
hs311295: Ans: [n*(a^x*cos(x))^n*(sin(x)-log(a)*cos(x))]/cos(x)
hs311295: hope u find u will find ur solution from this
kajalmishra7874: u find this by lebnitz theorem?
hs311295: ur engineering student
kajalmishra7874: yes
Answered by sadiaanam
0

Answer:

This is the nth derivative of a^x.cosx

Step-by-step explanation:

As per the data given in the question

we have to calculate

nth derivative of a^x.cosx

As per the question

It is given that a^x.cosx.

By using complex number we have to find nth derivative.

write a^x.cosx = a^{x}ka(a^{ix})=ka(a^{(1+i)x} )

calculate nth derivative of a^{(1+i)x}

\frac{da^{(1+i)x} }{dx}= (1+i)^{n}a^{(1+i)x}

Taking real part

\frac{d a^{x} cos x }{dx}=ka(1+i)^{n}a^{(1+i)x}

To simplify that we have to write

1+i = \sqrt{2}a^{\frac{i\pi }{4} }  trigonometric form of 1+i

(1+i)^n a^{ix}=\sqrt{2}a^{i(\frac{n\pi }{4}+x) }

Finally taking real part

\frac{d a^{x} cos x }{dx}=2^{\frac{n}{2} }a^{x}cos (\frac{n\pi }{4}+x)

Hence, this is the nth derivative of a^x.cosx.

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