find nth derivative of y =1 /(x+2)(x-1)
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Hi Mate!!
1 / ( x+2 ) ( x -1 ) = A / ( x +2 ) + B / ( x -1 )
A + B = 0
And
A + 2B = 1
On solving we get
A = 1 and B = -1
1 / ( x +2 ) -1 / ( x -1 )
Yntn. = N! ( x + 2 ) ^ -( N -1 ) - N! ( x -1 ) ^ -( N -1)
Ynth = N! { 1 / ( x + 2 ) ^ ( N -1 ) - 1 / ( x - 1 ) ^ ( N -1 )
1 / ( x+2 ) ( x -1 ) = A / ( x +2 ) + B / ( x -1 )
A + B = 0
And
A + 2B = 1
On solving we get
A = 1 and B = -1
1 / ( x +2 ) -1 / ( x -1 )
Yntn. = N! ( x + 2 ) ^ -( N -1 ) - N! ( x -1 ) ^ -( N -1)
Ynth = N! { 1 / ( x + 2 ) ^ ( N -1 ) - 1 / ( x - 1 ) ^ ( N -1 )
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