find nth differential coefficient of sin2x.cos3x
Answers
Answered by
2
Step-by-step explanation:
y=sin2xcos3x
(
dx
dy
)=
dx
d(sin2xcos3x)
=(
dx
dsin2x
)cos3x+sin2x(
dx
dcos3x
)
=[(cos2x)×2]cos3x+sin2x×(−sin3x)×3
=2cos2xcos3x−3sin2xsin3x
Answered by
0
Step-by-step explanation:
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