. Find nth term a, (general term of the A.P.) whose first term is a and
common difference is d. If pth term of an A.P. is q and the oth term is p.
prove that the nth term is (p + q - n).
[CBSE 2014]
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Solution
pth term = q
a+(p−1)d=q
qth term = p
a+(q−1)d=p
- Solving these equations,
we get,
d=−1
a=(p+q−1)
Thus,
nth term = a+(n−1)d=(p+q−1)+(n−1)×(−1)
=(p+q−n)
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