Find nth term of AP 1,3,5,7------and 2,4,6,8-----.is any term of both AP will
same clarify with reason.
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AP 1,3,5,7
a= 1 , d= 3-1=2
n=?
an= a+ ( n-1) d
= 1+( n-1) ×2
= 1+ 2n-2
= 2n -1---1
AP
2,4,6,8,...
a= 2
d= 4-2= 2
an =?
An = a+(n-1)d
= 2+(n-1) ×2
= 2+2n-2
= 2n--------2)
if nth term is equal then
From equation 1and 2
2n-1 = 2n
n-1= 2n/2
n-1= n
n= n-1
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