Find nth term of AP 13/5,7/5,1/5,-1...
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a = 13/5, d = -6/5
therefore, nth term = a + (n-1)d
= 13/5 + (n-1)(-6/5)
= 13/5 -6n/5 + 6/5
= 19/5 - 6n/5 = (19 - 6n)/5
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therefore, nth term = a + (n-1)d
= 13/5 + (n-1)(-6/5)
= 13/5 -6n/5 + 6/5
= 19/5 - 6n/5 = (19 - 6n)/5
Hope it helps,
If it does, plz mark as brainliest
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