Question

find nth term of sn = 2nsqare-n​

Answer 1

Answer:

4n-3

Step-by-step explanation:

sum of n ap= n/2 [2a +(n-1)d]

as per question

when n=1

first term =2 (n)^2-n

=1=a

sum till second term=2 (n)^2-n

=2 (2)^2-2

=6

now common difference =d= sum till second term -first term =6-2=4

hence nth term =a+(n-1)d

=1+(n-1)4

=1+4n-4= (-3 +4n)