Question

Find nth term of the series 1,1,2,3,4,9,8,27,16,81,32,243 in c program

Answer 1

Answer:

64

Step-by-step explanation:

There are two different alternating series

first is 1,2,4,8,16,32,....

second is 1,3,9,27,81,243,...

according to first series 1,2,4,8,16,32

second number is double of first

1x2 =2

2x2=4

4x2=8

8x2=16

16x2=32

32x2=64

therefore answer is 64

Answer 2

Answer:

$tn = {2}^{ \frac{n - 1}{2} } \: \: if \: n \: is \: odd \\ \: tn = {3}^{ \frac{n - 2}{2} } \: \: if \: n \: is \: even$

Step-by-step explanation:

$odd \: \: terms \\ 1 \: 2 \: 4 \: 8 \: . \: . \: . \: {2}^{ \frac{n - 1}{2} } \\ even \: \: terms \\ 1 \: 3 \: 9 \: 27 \: . \: . \: . \: {3}^{ \frac{n - 2}{2} }$