Question

find number of constituent atoms in 56g Na₂CO₃

Answer 1

0.5 mulecules..............

Answer 2

Hey friend, Harish here.

Here is you answer:
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The Given compound is -  Na₂CO₃

Mass of the compound = 56 g.

We know that,

Atomic mass of Na = 23. u

Atomic mass of C = 12 u

Atomic mass of O = 16 u

Then, Molecular mass of Na₂CO₃ = (23 × 2) + (12) + (16 × 3)

                                                 = 106 u.

No.of moles = Mass / Molecular mass.

                    = 56 / 106 = 0.5 Moles

Total number of atoms = 2 Na atoms + 1 C atom + 3 O atoms

                                     = 6 atoms.

We know that,

1 mole of a compound contains 6.02 × 10²³ molecules.

Then, 0.5 moles contains - (6.02 × 10²³) / 2 = 3.01 × 10²³ molecules.

Then No of constituent atoms = No of molecules × No of atoms in compound.

                                                = 3.01 × 10²³  × 6

                                                = 18.06 × 10²³ atoms.
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Hope my answer is  helpful to you.