Find number of field lines originating from a point charge of q = 8.854x10 -6 C.
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N= q/£o
= 8.854*10-6/8.854*10-12
= ten to the power of 6 Nm2c-1
= 8.854*10-6/8.854*10-12
= ten to the power of 6 Nm2c-1
Answered by
3
Answer:
E=10^6Nm2c-1
Explanation:
Whole explanation given below
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