Question

find number of hydrogen molecules present in 44.8 litre of hydrogen gas of NTP ?​

Answer 1

Given :

• Volume of hydrogen gas = 44.8 L at NTP
• Temperature at NTP = 293.15 K
• Pressure at NTP = 1atm

To find :

Number of hydrogen molecules present

Formula used :

1. PV = nRT
2. Number of molecules = Number of mole × Avogadro's Number

Here,

• P = Pressure of gas
• V = Volume of gas
• n = number of mole of gas
• R = gas constant
• T = Temperature of gas

Solution :

First of all we need to find number of mole of hydrogen gas present

By using ideal gas equation,

$\sf \implies \: 1atm \times 44.8L \: = \: n \times 293.15 \: K \times 0.082 \: {atm} \: L \: {K}^{( - 1)} {mol}^{ (- 1)}$

$\sf \implies \: \: n = \dfrac{ 1atm \times 44.8L \: }{293.15 \: K \times 0.082 \: {atm} \: L \: {K}^{( - 1)} {mol}^{ (- 1)}}$

$\sf \implies \: \: n = \: \dfrac{ 44.8 \: mol}{293.15 \times 0.082 \: }$

$\sf \implies \: \: n = \: \dfrac{ 44.8 \: mol}{24.04 }$

$\sf \implies \: \: n = \: 2.03$

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Now by using Formula we will find number of molecule of hydrogen .

➝ Number of molecules = 2.03 × 6.02 × 10²³

➝ Number of molecules = 12.22 × 10²³

➝ Number of molecules = 1.222 × 10²⁴

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ANSWER : 1.222 × 10²⁴ molecules