Find number of integer roots of equation x(x+1)(x+2)(x+3)=120
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x(x+1)(x+2)(x+3) = 120
So, x(x+1)(x+2)(x+3) = 2×3×4×5
So, x=2 is the integer root.
Also, x(x+1)(x+2)(x+3) = (-2)×(-3)×(-4)×(-5)
Here, now, x = (-5) is the integer root
Since the highest power of the variable x in the expression is 4, the equation must have 4 roots.
However, there are only two integer roots as shown.
So, x(x+1)(x+2)(x+3) = 2×3×4×5
So, x=2 is the integer root.
Also, x(x+1)(x+2)(x+3) = (-2)×(-3)×(-4)×(-5)
Here, now, x = (-5) is the integer root
Since the highest power of the variable x in the expression is 4, the equation must have 4 roots.
However, there are only two integer roots as shown.
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2
Answer:
Step-by-step explanation:
By solving we find that it has degree 4 so itbis biquadratic so. There are no real roots.
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