Math, asked by anuraagreddy74, 1 year ago

Find number of integer roots of equation x(x+1)(x+2)(x+3)=120

Answers

Answered by QGP
46
x(x+1)(x+2)(x+3) = 120
So, x(x+1)(x+2)(x+3) = 2×3×4×5

So, x=2 is the integer root.

Also, x(x+1)(x+2)(x+3) = (-2)×(-3)×(-4)×(-5)

Here, now, x = (-5) is the integer root

Since the highest power of the variable x in the expression is 4, the equation must have 4 roots.

However, there are only two integer roots as shown.
Answered by Anmolkumaarsiingh
2

Answer:

Step-by-step explanation:

By solving we find that it has degree 4 so itbis biquadratic so. There are no real roots.

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