Question

Find number of ions present in 222g of CaCl2​

Answer 1

Answer:

Molecular weight of CaCl2 = 111

1 mole weighs 111g

222g is 2 moles

1 mole of a substance contains Avogadros number of particles.

2 moles of CaCl2 contains 2*Avogadros number of molecules = 2*6.022*10^23 = 1.2*10^24

1.2*10^24 molecules of CaCl2 contains 1.2*10^24 Ca++ ions and 2*1.2*10^24 Cl- ions = 2.4*10^24 Cl ions