Find number of ions present in 222g of CaCl2
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Molecular weight of CaCl2 = 111
1 mole weighs 111g
222g is 2 moles
1 mole of a substance contains Avogadros number of particles.
2 moles of CaCl2 contains 2*Avogadros number of molecules = 2*6.022*10^23 = 1.2*10^24
1.2*10^24 molecules of CaCl2 contains 1.2*10^24 Ca++ ions and 2*1.2*10^24 Cl- ions = 2.4*10^24 Cl ions
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