Question

find number of line segments can be formed by given points such that no 3 points are colinear​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

please search on Google

I hope this answer help you

please mark be brainliest in

Answer:

1 by 1 + 6 ^ b - 1 + X ^ C minus A + 1 by 1 + X ^ a minus b + X ^ 3 - b + 1 by 1 + X ^ 3 - 3 + 6 ^ a minus b equal to

Step-by-step explanation:

x − 1. = a, y y − 1. = b, z z − 1. = c,. i.e., x = a a − 1. , y = b b − 1 .

Hope Helps ❤️