find number of oxygen atom presint in 4.4g of co2
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0
Answer:
1.2064e23 or 1.2064×10^23
Answered by
2
Explanation:
N/N°=wt/Mwt
N=4.4/44×N°
N=0.1N° molecule
CO2 contain 2oxy atom
Hence
N=0.1N°×2atom
N=0.2N° atom (N° Avogadro No.)
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