find number of oxygen atoms present in 100 mg of CaCO3
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Answered by
3
Explanation:
100 g of Calcium Carbonate (100,000 mg of Calcium Carbonate) has 3 moles of Oxygen atoms = 3 x 6.022 x 10^23 Oxygen atoms.
TriangulumEntangulum:
The user asked for 100mg not 100g.
Answered by
1
Answer:
18.066×10^20 oxygen atoms
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