Question

find number of photon in 6.62 J of radiation of frequency to
${10}^{12}hz$
​

Answer 1

Answer:

$e = \frac{nhc}{f} \\ 6.62 = \frac{n \times 6.62 \times {10}^{ - 34} \times 3 \times {10}^{8} }{ {10}^{ - 12 } } \\ n = {10}^{ - 12} \frac{1}{ {10}^{ - 34} \times 3 \times {10}^{8} } \\ n = 0.33 \times {10}^{14}$

Hope it helps.......

Answer 2

Answer:

$num \: of \: photons = {10}^{22}$

Explanation:

energy = no. of photons * h * frequncy

h=6.62*10^-34

6.62= n * 6.62*10^-34 * 10^12

n = 10^22