Question

find number of photons in 6.62 J of radiant energy of frequency 10^12 Hz . (take h=6.62*10^-34 J-s)

Answer 1

Answer:

$10^{22}$

Explanation:

Radiant  energy = hν = $(6.62*10^{-34} )(10^{12})=6.62*10^{-22}$

Given energy is 6.62 J

The number of photon = $\frac{6.62}{6.62*10^{-22} } = 10^{22}$

Answer 2

The number of photons is $10^{22}$.

Explanation:

Given that,

Energy of a photon, E = 6.62 J

Frequency of a photon, $f=10^{12}\ Hz$

Planck's constant, $h=6.62\times 10^{-34}\ J-s$

The energy of a photon is given by the formula as follows :

$E=nhf\\\\n=\dfrac{E}{hf}\\\\n=\dfrac{6.62\ J}{6.62\times 10^{-34}\ J-s\times 10^{12}\ Hz}\\\\n=10^{22}\ \text{photons}$

So, the number of photons is $10^{22}$. Hence, this is the required solution.

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Energy of a photon

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