find number of real values of x satisfying this |2x - x^2 - 2| = 2x - x^2 - 2
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Answer of value of x must be 1
2(1)-(1)^2-2==2(1)-1^2-2
2-1-2==2-1-2
-1===-1
2(1)-(1)^2-2==2(1)-1^2-2
2-1-2==2-1-2
-1===-1
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the solution is x=1,
because at LHS and RHS are absolutely same
because at LHS and RHS are absolutely same
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