Question

find number of straight line passing through point (2,4) and forming a triangle of 16 sq. cm with the co-ordinate axis ​

Answer 1

Answer:

$\frac{x}{4}+\frac{y}{8}=1$

Step-by-step explanation:

Let us assume that the equation of the straight line be $\frac{x}{a}+\frac{y}{b}=1$ ......... (1)

where it's X-intercept is at (a,0) and Y-intercept is at (0,b).

Now, the straight line (1) passes through the point (2,4), so, it will satisfy the equation (1).

So, $\frac{2}{a}+\frac{4}{b}=1$ ...... (2)

Again, it is given that the straight line makes a triangle with the coordinate axes whose area is 16 sq. cm

Hence, $\frac{1}{2}.a.b=16$

⇒$b=\frac{32}{a}$......... (3)

Putting this value of b in equation (2), we get,

$\frac{2}{a}+\frac{4}{\frac{32}{a}}=1$

⇒$\frac{2}{a}+\frac{a}{8}=1$

⇒a²-8a+16=0

⇒(a-4)²=0

⇒a=4 cm.

Now from equation 3, b=$\frac{32}{4}=8 cm$

Therefore, the equation of the straight line is

$\frac{x}{4}+\frac{y}{8}=1$  (Answer)

Answer 2

Answer:

answer is 3 sir please rechack