Find number of terms :
1 how many number of terms in ap 9,17,25.... taken so that tehier sum is 636?
2 how many number of terms in ap 63,60,57....taken so that their sum is 693?
pls ans asap
Answers
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Step-by-step explanation:
1qn Solution
sn=636, a=9 d=8 ,n=?
636=n/2(2a+(n-1)d)
636=n/2(18+8n-8)
636=n(5+4n)
4n^2+5n-636=0
4n^2-48n+53n-636=0
4n(n-12)+53(n-12)=0
n=-53/4,12
n value can't be negative so n=12,
our required terms is 12..
2)...
a=63,d=-3,n=?,Sn=693
Sn=n/2(126+(n-1)-3)
693 =n/2(126-3n+3)
693×2=n(129-3n)
1386=129n-3n^2
3n^2-129n+1386=0
3n^2-66n-63n+1386=0
3n(n-22)-63(n-22)=0
(3n-63)(n-22)=0
n=21,22
hope you understand
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