Question

find number of zeroes of polynomial x^2+1​

Answer 1

Answer:

x² + 1 will have two zeroes because it is a quadratic equation

#WMK

Answer 2

Step-by-step explanation:

p(x)=x^2+1

.•.p(x)=x^2+ox+1

a=1,b=0,c=1

discriminant,

d=b^2-4ac

d=0^2-4×1×1

$\huge{\pink{\boxed{\boxed{\boxed{\purple{\underline{\underline{\green{\mathbb{d=-4}}}}}}}}}}$.

since, d<0,

therefore, x^2+1 has no real zeroes.

:)