Question

find odd man out 525,39,24,426,636​

Answer 1

The given numbers are 525,39,24,426,636​.

In all the given numbers except 426, the first number is followed by its square.

In 525, the last two digits 25 are the square of the first digit 5.

In 39, the last digit 9 is the square of the first digit 3.

In 24, the last digit 4 is the square of the first digit 2.

In 636, the last two digits 36 are square of the first digit 6.

But the above pattern is not followed in 426 as 26 is not the square of 4.

Answer 2

We recall that the perfect square of a number is that number that is product of a number two times by itself.

Given : 525,39,24,426,636

In a given number, the number in the hundred places is followed by its perfect square.

$525\\5^2=25\\39\\3^2=9\\24\\2^2=4\\426\\4^2=16$

426 is an odd number because 4 is followed by 26 and 26 is not a perfect square of 4.

$636\\6^2=36$