Math, asked by khsuhi, 1 year ago

Find odd one out number from the group. 13,17,29,37,43,69,89​

Answers

Answered by Hansika4871
0

Given:

A series of numbers 13, 17, 29, 37, 43, 69, 89.

To Find:

The odd term in the above series.

Solution:

1. The given series is 13,17,29,37,43,69,89​.

2. Find the factors of every term,

=> Factors of 13 = 1, 13. 13 is a prime number.

=> Factors of 17 = 1, 17. 17 is a prime number.

=> Factors of 29 = 1, 29. 29 is a prime number.

=> Factors of 37 = 1, 37. 37 is a prime number.

=> Factors of 43 = 1, 43. 43 is a prime number.

=> Factors of 69 = 1, 3, 23, 69. 69 is a Composite number.

=> Factors of 89 = 1, 89. 89 is a prime number.

3. The number 69 is composite whereas the other terms are prime. Hence, 69 is the odd term in the given series.

Therefore, 69 is the odd number of the given series.

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