Question

find
of a
vertices
are
( (-1,4) (-6, 6)
the area of
(-39)
and​

Answer 1

Solution :

Given that , the vertices of triangles

Let `(x_(1),y_(1))to(-8,4)`

`(x_(2),y_(2))to(-6,6)`

and `(x_(3),y_(3))to(-3,9)`

we know that , the area of triangle with vertices `(x_(1),y_(1)),(x_(2),y_(2))and (x_(3),y_(3))`

`triangle=(1)/(2)[x_(1)(y_(2)-y_(3))+x_(2)(y_(3)-y_(1))+x_(3)+(y_(1)-y_(2))]`

`:.=(1)/(2)[-8(6-9)-6(9-4)+(-3)(4-6)]`

`=(1)/(2)[-8(-3)-6(5)-3(-2)]=(1)/(2)(24-30+6)`

`=(1)/(2)(30-30)=(1)/(2)(0)=0`

Hence , the required area of triangle is 0.

Step-by-step explanation: