Question

find
of
the Value of m, if (x-2) is the factor
the polynomial ax² - 6x² + mx +4.
​

Answer 1

Answer:

$x - 2 = 0 \\ x = 2 \\ p(x) = a {x}^{2} - 6 {x}^{2} + mx + 4 = 0 \\ a {(2)}^{2} - 6 {(2)}^{2} + m(2) + 4 = 0 \\ 4a - 24 + 2m + 4 = 0 \\ m = \frac{20 - 4a}{2} \\ \boxed{m = 10 - 4a} \\ \\ \red{\mathfrak{ \large{\underline{{Hope \: It \: Helps \: You}}}}} \\ \blue{\mathfrak{ \large{\underline{{Mark \: Me \: Brainliest}}}}}$