find one irrational number between 0.1 and 0.12
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Let, a = 0.1 = 0.10 And, b = 0.12 We observe that in the second decimal place a has digit 0 and b has digit 2, Therefore a < b .So, if we consider irrational numbers x = 0.11011001100011... y = 0.111011110111110... We find that, a < x < y < b Hence, x and y are required irrational numbers.
two-irrational-numbers-lying-between-0-1-and-0-12
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