Math, asked by aaria2801, 2 months ago

Find order of 6 in
(Z10,+)​

Answers

Answered by tanishgupta886
1

Step-by-step explanation:

Answer

LHS=cosA+sinA−1cosA−sinA+1

dividing Nr and Dr by sinA we get,

=sinAcosA+sinAsinA−sinA1sinAcosA−sinAsinA+sinA1

=cotA+1−cosecAcotA−1+cosecA

=cotA+1−cosecAcotA+cosecA−(cosec2A−cot2A)

=cotA+1−cosecA(cotA+cosecA)(1−cosecA+cotA)

=cotA+cosecA=RHS

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