Question

Find order, radicand and coefficient for ³√108​

Answer 1

$\bf\huge\pink{ANSWER}$

$\bf{ \sqrt[3]{108} = \sqrt[3]{27 \times 4} } \\ \\ = \bf{ \sqrt[3]{ {3}^{3} \times 4} } \\ \\ = \sqrt[3]{ {3}^{3} } \times \sqrt[3]{4} \\ \\ \bf \pink{law \: of \: radicle \: ii} \\ \\ \bf{3 \times \sqrt[3]{4}} \\ \\ \bf \pink{law \: of \: radicle \: i} \\ \\ \bf \purple{order = 3 } \\ \\ \bf \red{radicand = 4} \\ \\ \bf \blue{coefficient =3 }$