Math, asked by jahnavikaranwal, 8 months ago

find other zeroes of the polynomial 4 + 3 − 92 − 3 + 18,if it is given that two of its zeroes are √3 − √3.

Answers

Answered by shivu2010
0

Answer:

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Answered by opurvasaini
0

Answer:

P(X) x⁴+x³-9x²-3x+18

Zeros are: √3, -√3

Factor of zeros are ( x-√3 ), ( X+√3 )

(X)²- (√3)²

X²-3 is a factor

: Division:

X²-3) x⁴+x³-9x²-3x+18( x²+x-6

X²+0x-3x

_______

X³-6x-3x+18

X³+0x-3x

________

-6x²+18

-6x²+18

______

0

_______

Remainder is : x²+x-6

X²+x-6( middle term spitting )

X²+x-6

X²-2x+3x-6

X(x-2)3(x-2)

(X+3)(x-2)

X+3=0, x-2=0

X=-3, X=2

Other zeros are 2,-3

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