Find other zeroes of the polynomial p(x)=2x4 +7x3-19x2-14x +30 if two of its zeroes are √2 and -√2.
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Step-by-step explanation:
p(x)=2x4=7x3-19x2-14x=30
zeros = root2'-/2
therefore (x-/2)(x+/2)
after dividing the quetient will be = 2x2+7x-15
sorry i couldnot divide and show
remainder =0
therefore , d x Q + R
(x2-2)(2x2+7x-15)
(x2-2){2x2+(10-3)x-15}
(2x2+10x-3x-15)
{2x(x+5)-3(x+5)}
(2x-3)(x+5)
(2x-3)=0
x=3/2
x+5=0
x=-5
therefore,theother zeros are = 3/2,-5
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