Question

find other zeroes of the polynomial x  4 –7x 2 +12 if it is given that two of its zeroes are √3 and -√3. ​

Answer 1

$\huge{\mathcal\red{♡Answer:}}$

${x}^{4} - 7 {x}^{2} + 12 = 0 \\⇒ {x}^{4} - 3 {x}^{2} - 4 {x}^{2} + 12 = 0\\ ⇒ {x}^{2}( {x}^{2} - 3) - 4( {x}^{2} - 3) = 0 \\ ⇒ ( {x }^{2} - 3)( {x}^{2} - 4) = 0\\ ⇒ ( {x}^{2} - 3)(x + 2)(x -2) = 0 \\ \\∴{x }^{2} - 3= 0 \\ ⇒ {x}^{2} =3 \\ ⇒x =∓ \sqrt{3} \\ \\ ∴x + 2 = 0 \\ ⇒x = - 2 \\ \\ ∴x - 2 = 0 \\⇒ x = 2$

$\bold\green{\boxed{So,\:The\:other\:zeros\:of\:the\:Polynomial\:are\:2\:and\:-2}}$

$<marquee>  ❤♥❤ I hope you will be helped by this answer.  ❤♥❤   </marquee>$

$<marquee>  ♥❤♥ Please follow me and mark as brainliest. ♥❤♥  </marquee>$