Question

find other zeros of the polynomial x^4 + x cube - 9 x square - 3 x + 18 if it gets given the two of its zeros are under root 3 and - under root 3​

Answer 1

Answer:

P(X) x⁴+x³-9x²-3x+18

Zeros are: √3, -√3

Factor of zeros are ( x-√3 ), ( X+√3 )

(X)²- (√3)²

X²-3 is a factor

: Division:

X²-3) x⁴+x³-9x²-3x+18( x²+x-6

X²+0x-3x

_______

X³-6x-3x+18

X³+0x-3x

________

-6x²+18

-6x²+18

______

0

_______

Remainder is : x²+x-6

X²+x-6( middle term spitting )

X²+x-6

X²-2x+3x-6

X(x-2)3(x-2)

(X+3)(x-2)

X+3=0, x-2=0

X=-3, X=2

Other zeros are 2,-3 and

Hope it helps you