Question

find out 2 numbers where 1/7th sum of them is 4 and 1/4th difference is 1​

Answer 1

ANSWER :

The two numbers are 16 and 12

EXPLANATION :

Let the numbers be x and y

1/7 (x+y) = 4

x + y = 4×7

x + y = 28..........(1)

1/4(x-y) = 1

x - y = 4........(2)

Adding (1) and (2)

2x = 32

x = 16

x - y = 4

y = 16 - 4

y = 12

The two numbers are 16 and 12

FOLLOW ME

Answer 2

suppose the 1st no =x

and the 2nd no =y

A to Q,