Find out 3 numbers such that the product of the first and second is 24 that of the second and third is 48, and that of first and third is 32. I need proper answer.
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Answer:
the poem 5744444 first w a w
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Answer:
x,y,z
xy=24
yz=48
xz=32
x=(24/y)
(24/y)*z=32
yz=48,soz=(48/y)
(24/y)(48/y)=32
(1152/y&^2)=32
32y^2=1152y^2=36
y=6
x=4z=8
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