Find out ( A + B + C + D ) such that AB x CD = DDD, where AB & CB are two digit numbers & DDD is three digits number.
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AB×CD=DDDNow,DDD has a factors of D and 111.Also,111 has factors 3 and 37.i,e
DDD=(37×3×D)=AB×CDThus,
either AB or CD is 37 and other number is D×3.
Either D=5,37×(3×5)=55537×15=555A=3,B=7,C=1,D=5
A+B+C+D=16
or
D=7
37×(3×7)=77721×37=555A=2,B=1,C=3,D=7
A+B+C+D=13
DDD=(37×3×D)=AB×CDThus,
either AB or CD is 37 and other number is D×3.
Either D=5,37×(3×5)=55537×15=555A=3,B=7,C=1,D=5
A+B+C+D=16
or
D=7
37×(3×7)=77721×37=555A=2,B=1,C=3,D=7
A+B+C+D=13
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