Question

find out a quadratic polynomial whose zeroes are 4 and5 is..​

Answer 1

Answer:

So this is the required quadratic equation=>x²-9x+20=0

Answer 2

Answer:

this is from quadratic equation

so we have to know what is quadratic equation

ax²+bx+c =0 is the quadratic equation.

Step-by-step explanation:

given:

zero's of polynomial 4 and 5

zeros of polynomial are nothing but roots of polynomial.

we know x+y = -b/a

and xy = c/a

we will find this value

since x=4 and y= 5 which is given.

we know,

ax²- (x+y)x + xy= 0

we will find x+y and xy

4+5 =9

4×5= 20

put the value and get the answer

ax2 - 9x +20 =0

this is the required quadratic equation from the equation

HENCE THIS IS THE SOLUTION

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