Find out acceleration due to gravity when earth shrinks to radius r/2 and density of earth is constant.
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Answer:
g=GM/r^2
=GVd/r^2
= G(4/3)πr^3d/r^2 (Since earth is a sphere V=(4/3)πr^3)
g=(4/3)Gπrd
g=acceleration due to gravity
G=gravitational constant
M=Original mass of Earth
V=Original volume of Earth
d=density of Earth
r=Original radius of earth
New radius of earth=r1=r/2
New acceleration due to gravity
g1=(4/3)Gπr1d
=(4/3)Gπ(r/2)d
g1=g/2(Answer)
The acceleration due to gravity becomes half of the original value
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