Question

Find out acceleration over each of the intervals OA, AB and BC.(ii) Calculate distance covered in last 3 seconds.​

Answer 1

1] OA represents uniform acceleration since the slope of OA in the velocity - time graph is having a uniform positive slope. AB represents the uniform velocity of 20 ms ^-1 . since the slope of AB is zero. Hence , acceleration is zero.

2] After 10 s , the velocity is 20 Ms ^-1 ab To 30 s and after 30 s , the velocity is uniformly restarted to zero after 40 s.

3] Retardation is uniform and it is equal to the slope of BC ,i.e.

$slope \: of \: bc = \frac{bd}{dc} = \frac{20}{40 - 30} = {2 \: ms \: - }^{2}$

And acceleration = - 2 ms ^-2

4] Distance covered by the body between 10th and 30th second = 20 × 20 = 400 metres.

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Answer 2

Answer:

Step-by-step explanation:

1] 5 m/s2, 0, 2m/s2

2] After 10 s , the velocity is 20 Ms ^-1 ab To 30 s and after 30 s , the velocity is uniformly restarted to zero after 40 s.

3] Retardation is uniform and it is equal to the slope of BC ,i.e.

And acceleration = - 2 ms ^-2

4] Distance covered by the body between 10th and 30th second = 20 × 20 = 400 metres.