Find out all the four quantum numbers of the last electron of Calcium?(Z=20)
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Answer:
N=4
L=0
m=0
s= -¹/2
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Answered by
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E.C of Rubidium is (Z=37) = 1s 22s 22p 63s 23p 64s 23d 104p 65s 1
The valence electron is in 5s orbital.
Its 4 quantum numbers are- n=5,l=0,m=0,s=+ 21
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