Find out all the four values of quantum numbers for the second last electron of sulphur atom?
Answers
Answer:
Gold is a chemical element with the symbol Au (from Latin: aurum) and atomic number 79, making it one of the higher atomic number elements that occur naturally. In a pure form, it is a bright, slightly reddish yellow, dense, soft, malleable, and ductile metal. Chemically, gold is a transition metal and a group 11 element. It is one of the least reactive chemical elements and is solid under standard conditions. Gold often occurs in free elemental (native) form, as nuggets or grains, in rocks, in veins, and in alluvial deposits. It occurs in a solid solution series with the native element silver (as electrum), naturally alloyed with other metals like copper and palladium and also as mineral inclusions such as within pyrite. Less commonly, it occurs in minerals as gold compounds, often with tellurium (gold tellurides).
Explanation:
Sulfur has the electron configuration of 1s^2 2s^2 2p^6 3s^2 3p^4. We have to write a set of 4 quantum numbers for the 2 unpaired electrons
The two unpaired electrons are in the outermost sublevel, 3p.
Since the sublevel is 3p, we can see that the principal quantum number (n) = 3.
The angular quantum number (l) that corresponds with sublevel p is 1.
When l = 1, possible values for quantum number ml are -1, 0 and +1.
The value of quantum number ms can only be +1/2 or -1/2, denoting either a clockwise or counter-clockwise spin on the electron. Since those last two electrons are unpaired, they will have the same spin, and thus the same value for ms.