Question

Find out distance and displacement to the following.​

Answer 1

Answer:

$\boxed{ \mathfrak{here \: is \:ur \: help }}$

1)distance= 32km

displacement=7km

2)distance=4(l×b)

4(50m×20m)

4(100 m)

400m

displacement=0m(he returns to the same point)

Answer 2

$\huge \star \: \: \pink{ \underline{ \underline{ \orange{ \tt{ given : }}}}}$

• PQ = 3km

• QR = 5km

• RS = 7km

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$\large \star \: \underline{\tt{distance \: \: travelled : }}$

• P to Q to R to S to Q to R

$\large \: \: : \implies \:3 + 5 + 7 + 12 + 5 \\ \\ \large \: \: \boxed{ = 32\: km}$

∴ Distance travelled by car = 32km

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$\large \star \: \: \underline{\tt{displacement : }}$

$\: \: \: \: \: \large \rm \: \bull \: displacement = \\ \ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \rm \: final \: \: point \: \: reached$

$\large \: = \: \: p \: \: \: to \: \: \: r$

= 3 + 5

= 8

∴ Displacement of car = 8km

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$\large\star \: \: \blue{ \underline{ \underline{ \green{ \tt{ given : }}}}}$

• Shape of track = rectangle

• Length = 50m

• width (breadth) = 20m

• Travelled 2 times

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$\large \underline{ \underline{ \tt{ \: using \: \: formula : }}}$

$\large \rm \: perimeter = 2(length + breadth)$

$\large : \implies \rm \: perimeter = 4(length + breadth)$

• Since, Track is travelled 2 times

= 2 × 2(l + b)

= 4(lenght + breadth)

$\\ \large : \implies \tt \: perimeter = 4(50m + 20m) \\ \\ \large : \implies \tt \: perimeter = 4 \times 70m$

= 280m

∴ Distance travelled = 280m

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$\large \star \: \: \underline{\tt{displacement : }}$

$\\ \: \: \: \: \: \large \rm \: \bull \: displacement = \\ \ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \rm \: final \: \: point \: \: reached$

∴ Displacement = 0m

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