Question

find out elevation in boiling point of 2 molal aqueous solution

( 1 K of H O 0.56K Kg mol )​

Answer 1

We have to find the elevation in boiling point of 2 molal aqueous solution, given elevation constant is 0.56 K g/mol.

Solution : we know, $\Delta T_b=K_b m$

where $\Delta T_b$ is elevation in boiling point, $K_b$ is elevation constant and m is molality of solution.

Here $K_b$ = 0.56 Kg/mol , m = 2 molal

Now, $\Delta T_b$ = 0.56 × 2 = 1.12 K or °C

Therefore elevation in boiling point of solution is 1.12°C .

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