find out formula for the ionic solid substance, if A makes FCC , B occupies octahedral voids and C occupies tetrahedral voids.(atoms of 2 edges with one common corner is removed, i.e. 3 atoms)
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1)In this case A and B together make a FCC(or CCP) unit cell structure.
2)Each Corner and face-centered atom contribute 1/8 and 1/2 respectively towards one unit cell.
3)For one FCC unit cell, there are total 8 tetrahedral voids (2 along each body diagonal at 1/4 from eah corners,, all completely inside FCC unit cell so each contribute complete1)
4)Then the formula will be AB3C8D4.
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