Question

find out how many three digit numbers are divisible by 7. ​

Answer 1

Answer:

Step-by-step explanation:

Lowest three digit no. divisible by 3 = 102

Highest three digit no. divisible by 3 = 999

a=102

d=3

We know

a+(n-1)d = an

102 + (n-1) 3 = 999

= 102+3n-3 = 999

= 99+3n = 999

= 3n = 999-99

= n = 990/3

= n = 330

So 330 three digit terms are divisible by 3

Answer 2

a=105

d=7

an=994

$an = a + (n - 1)d$
994=105+(n-1)7
994-105=(n-1)7
889/7=n-1
127+1=n

n=128

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