Find out median for the data giren below Class interral Frequency ) 4 21-40 41-70 26 11-120 8 121-300 2.
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Explanation:
Class interval
Frequencies(f)
Cumulative frequencies(cf)
11−21
1
1
21−31
5
1+5=6
31−41
7
6+7=13
41−51
3
13+3=16
n=Σf=16
2
n
=
2
16
=8
Median =l+(
f
2
n
−cf
)×h
L= Lower limit of the median class =31
n=Σf= Total number of frequency =16
2
n
=
2
16
=8
So, the median class is 31−41
cf= Cumulative frequency of the class preceding the median class =6
f= Frequency of the median class =7
h= class width=10
Therefore, Median =l+(
f
2
n
−cf
)×h
=31+(
7
2
16
−6
)×10
=31+(
7
8−6
)×10
=31+4.28
=35.28
Hence, the median is 35.28
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