Question

Find out median from the following data :


Class intervals : 0-200 200-400400-600600-800800-1000 1000-1200


Frequency : 80 165 230 80 32 13​

Answer 1

Answer:

99999

Explanation:

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Answer 2

Answer:

hope it helps you

Explanation:

Here n=400. ∴

2n

=200

Class Frequency Cumulative frequency(c.f.)

0-100 64 64

100-200 62 64+62=126

200-300 84 126+84=210

300-400 72 210+72=282

400-500 66 282+66=348

500-600 52 348+52=400

Cumulative frequency greater than 200 is 210, corresponds to the class 200−300.

Class 200−300 is the median class

l=200, 2n

=200,cf=126,f=84 and c=100

Substituting the values in

M=l+ f( 2n−cf) ×c

=200+ 84200−126 ×100

=200+ 8474×100

=200+88.10

=288.10