Question

Find out moment of inertia of thick rod of length 'L' radius of crossection 'R' when axis of rotation is at one of the edge of the rod​

Answer 1

Answer:

ml2/3

Explanation:

Inertia (I')at axis passing through center of rod is ml2/12.

so ,inertia at l/2 distance of centre will be;

I = I' + m(l/2)2

=ml2/12+ml2/4

=ml2/3.