find out no. of atom in 52 amu of Helium
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2
Answer:-
(i) 1 mol of Ar = 6.022×1023atoms
∴ 52 mol of Ar = 52×6.022×1023atoms = 3.131×1025atoms
(ii) 1 atom of He = 4 u of He
4 u of He = 1 Atom of He
∴ 52 u of He = 1/4 × 52 = 13 atoms
(iii) 1 mol of He = 4 g = 6.022×1023atoms
∴ 52 g of He = (6.022×1023/4) × 52 atoms = 7.8286×1024atoms
(i) 1 mol of Ar = 6.022×1023atoms
∴ 52 mol of Ar = 52×6.022×1023atoms = 3.131×1025atoms
(ii) 1 atom of He = 4 u of He
4 u of He = 1 Atom of He
∴ 52 u of He = 1/4 × 52 = 13 atoms
(iii) 1 mol of He = 4 g = 6.022×1023atoms
∴ 52 g of He = (6.022×1023/4) × 52 atoms = 7.8286×1024atoms
Answered by
3
Atomic mass od 1 helium atom = 4 amu.
given mass = 52 amu.
No of atoms × maas of 1 helium atom = given mass
no. of atoms × 4 = 52
no. of atoms = 13
Therefore, 13 atoms of He are gonna be in 52 amu of mass.
given mass = 52 amu.
No of atoms × maas of 1 helium atom = given mass
no. of atoms × 4 = 52
no. of atoms = 13
Therefore, 13 atoms of He are gonna be in 52 amu of mass.
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