Question

Find out no. of electron present in 16gm of CO3 2-

Answer 1

Answer: Mass= 1.6gm

Moles=  

16

1.6

​

=0.1

Total number of molecules= 6.027×10  

23

×0.1=6.023×10  

22

 

Electron in 1 molecule= C+H×4⇒6+4=10

So in, 6.023×10  

22

 molecules ⇒10×6.023×10  

22

 

⇒6.023×10  

23

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